номер 86 гдз 8 класс алгебра Муравин Муравин

1)\begin{equation}\frac{a^{3}+6a^{2}}{a+2}+\frac{12a+8}{a+2} \end{equation} \begin{equation}\frac{a^{3}+6a^{2}+12a+8}{a+2}=\frac{\left ( a+2 \right )^{3}}{a+2}= \end{equation} \begin{equation}=\left ( a+2 \right )^{2} \end{equation}
(a + 2)² > 0 \begin{equation}a\epsilon R \end{equation} 2)\begin{equation}\frac{b^{4}+6b^{2}d^{2}+d^{4}}{b^{4}}-\frac{4b^{3}d+4bd^{3}}{b^{4}}= \end{equation} \begin{equation}=\frac{\left ( b^{2}+d^{2} \right )^{2}}{b^{4}}-\frac{4bd\left ( b^{2}+d^{2} \right )}{b^{4}}= \end{equation} \begin{equation}=\frac{\left ( b^{2}+d^{2} \right )^{2}-4bd\left ( b^{2}+d^{2} \right )}{b^{4}}= \end{equation} \begin{equation}=\frac{\left ( b^{2}+d^{2} \right )\left ( b^{2}+d^{2}-4bd \right )}{b^{4}}= \end{equation} \begin{equation}=\frac{\left ( b^{2}+d^{2} \right )\left ( b-d \right )^{2}}{b^{4}} \end{equation} \begin{equation}b^{2}>0   d^{2}> 0  \left ( b-d \right )^{2}> 0  b^{4}> 0 \end{equation} \begin{equation}\Rightarrow \frac{\left ( b^{2}+d^{2} \right )\cdot \left ( b-d \right )^{2}}{b^{4}}> 0 \end{equation}
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